Thermodynamics NCERT Solutions Class 11 Chemistry CBSE Study Material free pdf download
The NCERT Solutions for Class 11 Chemistry Chapter 6 Thermodynamics contains a vast collection of questions to practise. By practising these questions of Chapter 5 Thermodynamics, students can strengthen their problem solving skills as well as reasoning skills; these skills can be used in further chapters and real-life problems. These questions of Chapter 5 Thermodynamics can also help students to build a strong foundation for the chapter.
Access NCERT Solutions for Class 11 Chemistry Chapter – Thermodynamics
Access Video Lecture for Class 11 Chemistry Chapter – Thermodynamics
Topics included in NCERT Solutions for Class 11 Chemistry Chapter – Thermodynamics
- Thermodynamic Terms
- The System and the Surroundings
- Types of Thermodynamic Systems
- State of the System
- Internal Energy as a State Function
- Applications
- Work
- Enthalpy, H
- Measurement of ΔU and ΔH: Calorimetry
- Enthalpy Change and Reaction Enthalpy
- Enthalpies for Different Types of Reactions
- Spontaneity
- Gibbs Energy Change and Equilibrium
NCERT Problems of Chapter Thermodynamics
* Note : The Solutions of below problems are above in the pdf file.
Q-1: Choose the correct answer. A thermodynamic state function is a quantity
(i) used to determine heat changes
(ii) whose value is independent of the path
(iii) used to determine pressure-volume work
(iv) whose value depends on temperature only
Q-2: For the process to occur under adiabatic conditions, the correct condition is:
(i) ∆T = 0 (ii) ∆p = 0
(iii) q = 0 (iv) w = 0
Q-3: The enthalpies of all elements in their standard states are:
(i) Unity (ii) Zero
(iii) < 0 (iv) Different for every element
Q-4: ∆U0 of combustion of methane is – X kJ mol–1. The value of ∆H0 is
Q-5: The enthalpy of combustion of methane, graphite and dihydrogen at 298 K are –890.3 kJ mol–1 –393.5 kJ mol–1, and –285.8 kJ mol–1, respectively. Enthalpy of the formation of CH4 (g) will be
(i) -74.8 kJ
(ii) -52.27 kJ
(iii) +74.8 kJ
(iv) +52 kJ
Q-6: A reaction, A + B → C + D + q, is found to have a positive entropy change. The reaction will be
(i) possible at high temperature
(ii) possible only at low temperature
(iii) not possible at any temperature
(iv) possible at any temperature
Q-7: In a process, 701 J of heat is absorbed by a system, and 394 J of work is done by the system. What is the change in internal energy for the process?
Q-8: The reaction of cyanamide, NH2CN(s), with dioxygen was carried out in a bomb calorimeter, and ∆U was found to be –742.7 kJ mol–1 at 298 K. Calculate the enthalpy change for the reaction at 298 K.
NH2CN(g) + 3/2 O2(g) → N2(g) + CO2(g) + H2O(l)
Q-9: Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from 35°C to 55°C. The molar heat capacity of Al is 24 J mol–1 K–1.
Q-10: Calculate the enthalpy change on freezing of 1.0 mol of water at 10.0°C to the ice at –10.0°C. ∆fusH = 6.03 kJ mol–1 at 0°C.
Q-11 Enthalpy of combustion of carbon to CO2 is –393.5 kJ mol–1. Calculate the heat released upon the formation of 35.2 g of CO2 from carbon and dioxygen gas.
Q-12: Enthalpies of formation of CO (g), CO2 (g), N2O (g) and N2O4 (g) are –110, – 393, 81 and 9.7 kJ mol–1, respectively. Find the value of ∆rH for the reaction:
N2O4(g) + 3CO(g) → N2O(g) + 3 CO2(g)
Q-13: Given N2 (g) + 3H2 (g) → 2NH3 (g) ; ∆rH0= –92.4 kJ mol–1
What is the standard enthalpy of the formation of NH3 gas?
Q-14: Calculate the standard enthalpy of formation of CH3OH(l) from the following data:
CH3OH(l) + 3/2 O2(g) → CO2(g) + 2H2O(l);
Q-15: Calculate the enthalpy change for the process
CCl4(g) → C(g) + 4Cl(g) and determine the value of bond enthalpy for C-Cl in CCl4(g).
Q-16: For an isolated system, ∆U = 0, what will be ∆S?
Q-17: For the reaction at 298K,
2A + B → C
At what temperature will the reaction become spontaneous considering to be constant over the temperature range?
Q-18: For the reaction
2Cl(g) → Cl2(g)
What are the signs of ΔS and ΔG ?
Q-19: For the reaction
2A(g) + B(g) → 2D(g)
Calculate
2A(g) + B(g) → 2D(g)
Q-20: The equilibrium constant for a reaction is 10. What will be the value of ∆G0? R = 8.314 JK–1 mol–1, T = 300 K.
Q-21: Comment on the thermodynamic stability of NO(g), given,
(1/2)N2(g) + (1/2)O2(g) → NO(g);
NO(g) + (1/2)O2(g) → NO2(g);
Q-22: Calculate the entropy change in surroundings when 1.00 mol of H2O(l) is formed under standard conditions. ∆f H0= –286 kJ mol–1.
NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics PDF
The Chapter 6 Thermodynamics Chapter 6 Thermodynamics can be a bit confusing if students are not able to understand the concepts properly. For that purpose students need to start practising Chapter 6 Thermodynamics questions from the NCERT textbook. After practising those questions, students can prefer referring to the NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics PDF which is available in the ANAND CLASSES website.
Exercise Wise NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics
In the NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics, a plethora of exercises are given so that students can understand the concepts as well as can solve confusions then and there. By practising exercise wise questions, students can learn to approach different questions of Chapter 5 Thermodynamics in different and creative ways.
Formula wise NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics
The questions in the NCERT Solutions for Class 11 Chemistry Chapter 6 Thermodynamics are arranged according to each and every formula. By practising the questions of Chapter 5 Thermodynamics formula wise, students can become more confident while applying the formulas. By applying the right formulas in the right questions of Chapter 5 Thermodynamics, students can score good marks in those questions.
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- Hints and Solutionss are Given: In the NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics PDF, hints and Solutionss are given so that students can easily solve all their doubts and confusions.
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- Diagrams are Given: Diagrams are generally considered to be visual representation of the Class 11 Chapter 6 Thermodynamics Chapter 5 Thermodynamics questions and concepts; the same is followed in NCERT Solutions.
- Available in the PDF: The NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics is available in the PDF so that students can access answers whenever they want to.
Frequently Asked Questions on NCERT Solutions for Class 11 Chemistry Chapter 5
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- After Completing the Chapter: Students can prefer utilising the NCERT Solutions for Class 11 Chemistry Chapter 6 Thermodynamics revision after completing the chapter thoroughly.
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About ANAND CLASSES NCERT Solutions
The NCERT Solutions for Class 11 Chemistry Chapter 5 provided on this page contains all the intext and exercise questions listed in Chapter 5 of the NCERT Chemistry textbook for Class 11. It, therefore, covers many important questions that could be asked in the annual examinations.
Furthermore, detailed explanations are provided for every solution by the subject-matter experts at ANAND CLASSES. This makes the NCERT Solutions provided by ANAND CLASSES very student-friendly and concept-focused. These NCERT Solutions for Class 11 Chemistry can help students develop a strong foundational base for all the important concepts included in the CBSE syllabus of both Class 11 as well as competitive exams. Also, in cases where students face difficulty while going through the NCERT Class 11 Chemistry Solutions, the ANAND CLASSES support team is always available to clear their doubts.
To know more about the difference between system and surrounding, the difference between closed, open and isolated systems, internal energy, heat, work, the first law of thermodynamics, calculation of energy change, the correlation between ∆U and ∆H, Hess’s law, extensive and intensive properties, and ∆G, register with ANAND CLASSES now!.
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